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Proof step 9 from proof gcd-div-rest (previous step)

gcd(i, j) * i0 = i, i = i1 * gcd(i, j) + j0, abs(j0) < gcd(i, j) ⊦ j0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 10:
gcd(i, j) * i0 = i1 * gcd(i, j) + j0, gcd(i, j) * i0 = i, i = i1 * gcd(i, j) + j0, abs(j0) < gcd(i, j) ⊦ j0 = 0

Rule argument

fma: gcd(i, j) * i0 = i1 * gcd(i, j) + j0

Additional information

Used formulas: gcd(i, j) * i0 = i1 * gcd(i, j) + j0