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Proof step 2 from proof gcd-divides-01 (previous step)

j0 | gcd(i, j) ⊦ j0 | j

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: int-gcd inst: name: gcd-divides-both seq: ⊦ j | gcd(i, i0) → j | i ∧ j | i0 subst: [j, i, i0] → [j0, i, j] flags: current, []

Additional information

Used terms: j0, i, j