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Proof step 18 from proof gcd-divides-both (previous step)

j | abs(i0) ⊦ i0 = 0, j | i0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-gcd inst: name: div-abs-02 seq: ⊦ i | abs(j) ↔ i | j subst: [j, i] → [i0, j] flags: rewrite, current

Additional information

Used terms: i0, j