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Proof step 3 from proof gcd-max-prop (
previous step
)
∃ i1. i0 * i1 = i, i0 | j ⊦ i0 | gcd(i, j)
User applied rule exists left
And obtained the following new goals
Proof step 4
:
i0 * i1 = i, i0 | j ⊦ i0 | gcd(i, j)
Rule argument
pos: left 1
Additional information