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Proof step 11 from proof gcd-mod-one (previous step)

j * i1 < 0, i1 < 0, gcd(i, j) = 1, i * i0 = j * i1 + 1, 0 < j, 1 < j, 0 < i, 1 < i, 0 ≤ i0 ⊦ (i * i0) % j = 1

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: j * i1 + 1 ≤ 0

Additional information

Used simplifier rules: zero-ls: ⊦ 0 < i → (i * j < 0 ↔ j < 0); from specification int-mult%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult%numle-03: ⊦ i + (* j) ≤ (* j0) ↔ i ≤ j0 - j; from specification int-abs%mone-05: ⊦ i ≤ ~1 ↔ i < 0; from specification int-abs%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: j * i1 + 1 ≤ 0