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Proof step 2 from proof gcd-negone-eq (previous step)

~1 = j2 / gcd(i2, j2) ⊦ j2 + gcd(i2, j2) = 0

User applied rule cut formula

And obtained the following new goals

Proof step 3:
1 = ~ j2 / gcd(i2, j2), ~1 = j2 / gcd(i2, j2) ⊦ j2 + gcd(i2, j2) = 0
Proof step 5:
~1 = j2 / gcd(i2, j2) ⊦ 1 = ~ j2 / gcd(i2, j2), j2 + gcd(i2, j2) = 0

Rule argument

fma: 1 = ~ j2 / gcd(i2, j2)

Additional information

Used formulas: 1 = ~ j2 / gcd(i2, j2)