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Proof step 10 from proof gcd-one-eq (previous step)

j2 / gcd(i2, j2) = 1, 0 < j2, 0 < gcd(i2, j2) ⊦ j2 = 0, gcd(i2, j2) = j2, gcd(i2, j2) = 0, gcd(i2, j2) | j2

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: int-gcd inst: name: gcd-div2 seq: ⊦ gcd(i, j) | j subst: [i, j] → [i2, j2] flags: current, []

Additional information

Used terms: i2, j2