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Proof step 1 from proof gcd-rec-sub-01 (conclusion)

⊦ gcd(i, j) = gcd(i, j - i)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 2:
j = i0 + i ⊦ gcd(i, j) = gcd(i, i0)

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, i, i0] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, i, i0