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Proof step 37 from proof gcd-rec-sub-01 (previous step)

abs(i0) < abs(i), i < 0, 0 < i0 ⊦ gcd(i, i0 - abs(i)) = gcd(abs(i), abs(i0)), i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 38:
⊦ gcd(i, j) = gcd(j, i)
Proof step 39:
abs(i0) < abs(i), i < 0, 0 < i0 ⊦ gcd(i, i0 - abs(i)) = gcd(abs(i0), abs(i)), i = 0

Rule argument

spec: int-gcd inst: name: gcd-com seq: ⊦ gcd(i, j) = gcd(j, i) subst: [j, i] → [abs(i0), abs(i)] flags: rewrite, current

Additional information

Used terms: abs(i0), abs(i)