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Proof step 44 from proof gcd-rec-sub-01 (previous step)

abs(i0 - abs(i)) = abs(i) - abs(i0), 0 < abs(i0) ∧ abs(i0) < abs(i), abs(i0) < abs(i), i < 0, 0 < i0 ⊦ gcd(abs(i), abs(i0 - abs(i))) = gcd(abs(i0), abs(i) - abs(i0)), i = 0

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

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