[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 61 from proof gcd-rec-sub-01 (previous step)

0 < i, i0 < 0 ⊦ abs(i) < abs(i0), i0 = 0, gcd(abs(i), abs(i0 + i)) = gcd(abs(i), abs(i0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 62:
⊦ ¬ i < j ↔ ¬ ¬(i = j ∨ j < i)
Proof step 63:
0 < i, i0 < 0 ⊦ ¬(abs(i) = abs(i0) ∨ abs(i0) < abs(i)), i0 = 0, gcd(abs(i), abs(i0 + i)) = gcd(abs(i), abs(i0))

Rule argument

spec: int-basic1 inst: name: l seq: ⊦ ¬ i < j ↔ ¬ ¬(i = j ∨ j < i) subst: [j, i] → [abs(i0), abs(i)] flags: rewrite

Additional information

Used terms: abs(i0), abs(i)