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Proof step 23 from proof gcd-rec-sub-03 (previous step)

abs(i0 + i) = i0 - abs(i), abs(i) < i0, i < 0 ⊦ i0 < 0, gcd(abs(i), i0 - abs(i)) = gcd(abs(i0 + i), abs(i0)), 0 < i ∧ i < i0 + i

User applied rule insert equation

And obtained the following new goals

Proof step 24:
abs(i) < i0, i < 0 ⊦ i0 < 0, gcd(abs(i), i0 - abs(i)) = gcd(i0 - abs(i), abs(i0)), 0 < i ∧ i < i0 + i

Rule argument

pos: left 1 flags: discard

Additional information