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Proof step 27 from proof gcd-rec-sub-03 (previous step)

abs(i0) - (i0 - abs(i)) = abs(i), 0 < i0 - abs(i) ∧ i0 - abs(i) < abs(i0), abs(i) < i0, i < 0 ⊦ i0 < 0, gcd(abs(i), i0 - abs(i)) = gcd(abs(i0), abs(i0) - (i0 - abs(i))), 0 < i ∧ i < i0 + i

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

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