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Proof step 40 from proof gcd-rec-sub-03 (previous step)

¬(0 < abs(i) - abs(i0) ∧ abs(i) - abs(i0) < abs(i)), i < 0 ⊦ abs(i) < i0, i0 < 0, gcd(abs(i) - abs(i0), abs(i)) = gcd(abs(i) - abs(i0), abs(i0)), 0 < i ∧ i < i0 + i

User applied rule prop simplification

And obtained the following new goals

Rule argument

pos: left 1

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