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Proof step 52 from proof gcd-rec-sub-03 (previous step)

0 ≤ i ⊦ gcd(i, i0 + i) = gcd(i0 + i, i0), 0 < i ∧ i < i0 + i

User applied rule cut formula

And obtained the following new goals

Proof step 53:
i = 0, 0 ≤ i ⊦ gcd(i, i0 + i) = gcd(i0 + i, i0), 0 < i ∧ i < i0 + i
Proof step 56:
0 ≤ i ⊦ i = 0, gcd(i, i0 + i) = gcd(i0 + i, i0), 0 < i ∧ i < i0 + i

Rule argument

fma: i = 0

Additional information

Used formulas: i = 0