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Proof step 57 from proof gcd-rec-sub-03 (previous step)

0 < i ⊦ i = 0, gcd(i, i0 + i) = gcd(i0 + i, i0), i < i0 + i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 58:
⊦ i ≥ j ↔ ¬ i < j
Proof step 59:
0 < i ⊦ i = 0, gcd(i, i0 + i) = gcd(i0 + i, i0), ¬ i ≥ i0 + i

Rule argument

spec: int-abs inst: name: ge-def seq: ⊦ i ≥ j ↔ ¬ i < j subst: [j, i] → [i0 + i, i] flags: rewrite

Additional information

Used terms: i0 + i, i