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Proof step 71 from proof gcd-rec-sub-03 (previous step)

abs(i0) < abs(i), i0 < i, 0 < i, i0 < 0 ⊦ i0 = 0, i = 0, gcd(abs(i), abs(i) - abs(i0)) = gcd(abs(i) - abs(i0), abs(i0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 72:
⊦ gcd(i, j) = gcd(j, i)
Proof step 73:
abs(i0) < abs(i), i0 < i, 0 < i, i0 < 0 ⊦ i0 = 0, i = 0, gcd(abs(i) - abs(i0), abs(i)) = gcd(abs(i) - abs(i0), abs(i0))

Rule argument

spec: int-gcd inst: name: gcd-com seq: ⊦ gcd(i, j) = gcd(j, i) subst: [j, i] → [abs(i) - abs(i0), abs(i)] flags: rewrite, current

Additional information

Used terms: abs(i) - abs(i0), abs(i)