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Proof step 85 from proof gcd-rec-sub-03 (previous step)

0 < abs(i0) - abs(i) ∧ abs(i0) - abs(i) < abs(i0), i0 < i, 0 < i, i0 < 0 ⊦ abs(i0) < abs(i), i0 = 0, i = 0, gcd(abs(i), abs(i0) - abs(i)) = gcd(abs(i0), abs(i0) - (abs(i0) - abs(i)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 86:
⊦ i - (i - j) = j
Proof step 87:
0 < abs(i0) - abs(i) ∧ abs(i0) - abs(i) < abs(i0), i0 < i, 0 < i, i0 < 0 ⊦ abs(i0) < abs(i), i0 = 0, i = 0, gcd(abs(i), abs(i0) - abs(i)) = gcd(abs(i0), abs(i))

Rule argument

spec: int-abs inst: name: sub-same seq: ⊦ i - (i - j) = j subst: [j, i] → [abs(i), abs(i0)] flags: rewrite

Additional information

Used terms: abs(i), abs(i0)