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Proof step 2 from proof gcd-rec-sub (previous step)

i < j, 0 < i, 0 < j, 1 < j ⊦ gcd(i, j) = gcd(i, j - i)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
j = i0 + i, i < j, 0 < i, 0 < j, 1 < j ⊦ gcd(i, j) = gcd(i, i0)

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, i, i0] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, i, i0