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Proof step 4 from proof gcd-rec-sub (previous step)

0 < i0, 1 < i0 + i, 0 < i ⊦ gcd(i, i0 + i) = gcd(i, i0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ gcd(i, j) = gcd(j, i)
Proof step 6:
0 < i0, 1 < i0 + i, 0 < i ⊦ gcd(i0 + i, i) = gcd(i, i0)

Rule argument

spec: int-gcd inst: name: gcd-com seq: ⊦ gcd(i, j) = gcd(j, i) subst: [j, i] → [i0 + i, i] flags: rewrite, current

Additional information

Used terms: i0 + i, i