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Proof step 1 from proof gcd-same (conclusion)

⊦ i ≠ 0 → gcd(i, i) = abs(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ gcd(i, j) = gcd(abs(i), abs(j))
Proof step 3:
⊦ i ≠ 0 → gcd(abs(i), abs(i)) = abs(i)

Rule argument

spec: int-gcd inst: name: gcd-abs-rew-02 seq: ⊦ gcd(i, j) = gcd(abs(i), abs(j)) subst: [j, i] → [i, i] flags: rewrite, current

Additional information

Used terms: i, i