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Proof step 15 from proof gcd-zero-05 (previous step)

0 ≤ gcd(i0, j0), gcd(i, j) = ~ gcd(i0, j0), 0 < gcd(i, j) ⊦ gcd(i, j) = 0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: discard

Additional information

Used simplifier rules: gcd-zero-02: ⊦ ¬ gcd(i, j) < 0;%neg-10: ⊦ ~ i = 0 ↔ i = 0; from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%neg: ⊦ 0 < ~ i ↔ i < 0; from specification int-abs