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Proof step 4 from proof gcd-zero-05 (previous step)

gcd(i0, j0) = ~ gcd(i, j) ⊦ gcd(i0, j0) = 0 ∧ gcd(i, j) = 0

User applied rule insert equation

And obtained the following new goals

Proof step 5:
gcd(i0, j0) = ~ gcd(i, j) ⊦ ~ gcd(i, j) = 0 ∧ gcd(i, j) = 0

Rule argument

pos: left 1 flags:

Additional information