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Proof step 7 from proof gcd-zero-05 (previous step)

gcd(i0, j0) = ~ gcd(i, j) ⊦ gcd(i, j) = 0 ∧ gcd(i, j) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
gcd(i, j) + gcd(i0, j0) = 0 ⊦ gcd(i, j) = 0

Rule argument

Additional information

Used simplifier rules: negeq: ⊦ ~ i = j ↔ i + j = 0; from specification int-abs