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Proof step 1 from proof isSquare-mult-aux (conclusion)

j0 * j0 = j * i * i, 0 < j0, 0 < j, 0 < i ⊦ i = 0, isSquare(j)

User applied rule induction

And obtained the following new goals

Proof step 2:
j0 * j0 = j * i * i ∧ 0 < j0 ∧ 0 < j ∧ 0 < i, ∀ j1, j, i. i→n(j1) < i→n(j0) → j1 * j1 = j * i * i ∧ 0 < j1 ∧ 0 < j ∧ 0 < i → i = 0 ∨ isSquare(j) ⊦ i = 0 ∨ isSquare(j)

Rule argument

indvar: i→n(j0) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(j0)