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Proof step 32 from proof isSquare-mult-aux (previous step)

¬(prime(max_prime_divisor(j0)) ∧ ¬ max_prime_divisor(j0) | j * i * i), max_prime_divisor(j0) * i0 * max_prime_divisor(j0) * i0 = j * i * i, max_prime_divisor(j0) * i0 = j0, 0 < i, 0 < j, 0 < max_prime_divisor(j0) * i0, ∀ j1, j, i. i→n(j1) < i→n(max_prime_divisor(j0) * i0) → j1 * j1 = j * i * i ∧ 0 < j1 ∧ 0 < j ∧ 0 < i → i = 0 ∨ isSquare(j) ⊦ i = 0, isSquare(j), prime(max_prime_divisor(j0) * i0)

User applied rule prop simplification

And obtained the following new goals

Rule argument

pos: left 1

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