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Proof step 69 from proof isSquare-mult-aux (previous step)

max_prime_divisor(j0) * i0 * j0 = j * i * i, max_prime_divisor(j0) * i0 = j0, prime(max_prime_divisor(j0)), 0 < i, 0 < j, 0 < j0, ∃ i0. max_prime_divisor(j0) * i0 = j, ∀ j1, j, i. i→n(j1) < i→n(j0) → j1 * j1 = j * i * i ∧ 0 < j1 ∧ 0 < j ∧ 0 < i → i = 0 ∨ isSquare(j) ⊦ i = 0, max_prime_divisor(j0) | i, isSquare(j), prime(j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 70:
max_prime_divisor(j0) * i0 * j0 = (max_prime_divisor(j0) * i1) * i * i, max_prime_divisor(j0) * i0 = j0, prime(max_prime_divisor(j0)), 0 < i, 0 < j0, 0 < max_prime_divisor(j0) * i1, ∀ j1, j, i. i→n(j1) < i→n(j0) → j1 * j1 = j * i * i ∧ 0 < j1 ∧ 0 < j ∧ 0 < i → i = 0 ∨ isSquare(j) ⊦ i = 0, max_prime_divisor(j0) | i, isSquare(max_prime_divisor(j0) * i1), prime(j0)

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs