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Proof step 73 from proof isSquare-mult-aux (previous step)

i0 * j0 = i * i * i1, max_prime_divisor(j0) * i0 = j0, prime(max_prime_divisor(j0)), 0 < i, 0 < j0, 0 < max_prime_divisor(j0) * i1, ∀ j1, j, i. i→n(j1) < i→n(j0) → j1 * j1 = j * i * i ∧ 0 < j1 ∧ 0 < j ∧ 0 < i → i = 0 ∨ isSquare(j) ⊦ i = 0, max_prime_divisor(j0) = 0, max_prime_divisor(j0) | i, isSquare(max_prime_divisor(j0) * i1), prime(j0)

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: i0 * j0 = max_prime_divisor(j0) * i0 * i0

Additional information

Used simplifier rules: neq-not-zero: ⊦ i * j ≠ i * j0 → i ≠ 0; (forward) from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult%eq-nonzero: ⊦ i ≠ 0 → (i * j = i * j0 ↔ j = j0); from specification int-mult Used formulas: i0 * j0 = max_prime_divisor(j0) * i0 * i0