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Proof step 21 from proof isSquare-mult (previous step)

abs(j0) = abs(j1) * abs(i) ⊦ i = 0, ∃ j. abs(j) = abs(j1)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: j1

Additional information

Used terms: j1