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Proof step 9 from proof isSquare-mult (previous step)

abs(i) = 0 ∨ isSquare(abs(j)), abs(j0) * abs(j0) = abs(j) * abs(i) * abs(i), j0 * j0 = j * i * i ⊦ i = 0, isSquare(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
abs(j0) * abs(j0) = abs(j) * abs(i) * abs(i), j0 * j0 = j * i * i, isSquare(abs(j)) ⊦ i = 0, isSquare(j)

Rule argument

Additional information

Used simplifier rules: abs-07: ⊦ abs(i) = 0 ↔ i = 0; from specification int-abs