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Proof step 2 from proof max_prime_divisor-divides-02 (previous step)

j | i / max_prime_divisor(i), prime(j), 2 ≤ i, 0 ≤ i, 0 < i ⊦ prime(i), j | i

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ ¬ prime(i) ∧ 2 ≤ i → max_prime_divisor(i) | i
Proof step 4:
¬ prime(i) ∧ 2 ≤ i → max_prime_divisor(i) | i, j | i / max_prime_divisor(i), prime(j), 2 ≤ i, 0 ≤ i, 0 < i ⊦ prime(i), j | i

Rule argument

spec: inst: name: max_prime_divisor-divides seq: ⊦ ¬ prime(i) ∧ 2 ≤ i → max_prime_divisor(i) | i subst: [i] → [i] flags: current, []

Additional information

Used terms: i