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Proof step 1 from proof max_prime_divisor-divides-03 (conclusion)

⊦ ¬ prime(i) ∧ 2 ≤ i ∧ prime(j) ∧ j | i ∧ j ≠ max_prime_divisor(i) → j | i / max_prime_divisor(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
2 ≤ i, prime(j), j | i, 0 ≤ i, 0 < i ⊦ j = max_prime_divisor(i), j | i / max_prime_divisor(i), prime(i)

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs