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Proof step 1 from proof max_prime_divisor-ge2 (conclusion)

⊦ ¬ prime(i) ∧ 2 ≤ i → 2 ≤ i / max_prime_divisor(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
2 ≤ i, i / max_prime_divisor(i) < 2, 0 ≤ i, 0 < i, i / max_prime_divisor(i) < i ⊦ prime(i)

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs