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Proof step 20 from proof max_prime_divisor-ge2 (previous step)

max_prime_divisor(i) = i, 2 ≤ i, 0 ≤ i, 1 < i, 0 < i ⊦ prime(i)

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: inst: name: max_prime_divisor-prime seq: ⊦ ¬ prime(i) ∧ 2 ≤ i → prime(max_prime_divisor(i)) subst: [i] → [i] flags: current, []

Additional information

Used terms: i