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Proof step 6 from proof max_prime_divisor-nle (
previous step
)
⊦ j | i ∧ prime(j) ∧ j < i ∧ (∀ j0. j < j0 ∧ j0 < i ∧ prime(j0) → ¬ j0 | i) → max_prime_divisor(i) = j
Lemma
max_prime_divisor-def