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Proof step 2 from proof mod-gcd-01 (
previous step
)
⊦ i % gcd(i, j) = 0, j = 0
User applied rule insert lemma
And obtained the following new goals
Proof step 3
:
⊦ i ≠ 0 → i % gcd(i, j) = 0
Proof step 4
:
j ≠ 0 → j % gcd(j, i) = 0 ⊦ i % gcd(i, j) = 0, j = 0
Rule argument
spec: int-gcd inst: name: mod-gcd seq: ⊦ i ≠ 0 → i % gcd(i, j) = 0 subst: [i, j] → [j, i] flags: current, []
Additional information
Used terms: j, i