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Proof step 2 from proof mod-gcd (previous step)

⊦ i % gcd(i, j) = 0, i = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ gcd(i, j) | i
Proof step 4:
gcd(i, j) | i ⊦ i % gcd(i, j) = 0, i = 0

Rule argument

spec: int-gcd inst: name: gcd-div1 seq: ⊦ gcd(i, j) | i subst: [i, j] → [i, j] flags: current, []

Additional information

Used terms: i, j