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Proof step 18 from proof mod-square-10 (previous step)

prime(5) ∧ ¬ 5 | 4 * i0 * i0 → 5 * 2 * j ≠ 4 * i0 * i0, 4 * i0 * i0 = j * 10 ⊦ (2 * i0) % 10 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: prime-5: ⊦ prime(5);%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult