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Proof step 4 from proof mod-square-10 (previous step)

⊦ (∃ j0. i * i = j0 * 10) ↔ i % 10 = 0

User applied rule case distinction

And obtained the following new goals

Proof step 5:
∃ j0. i * i = j0 * 10 ⊦ i % 10 = 0
Proof step 28:
i % 10 = 0 ⊦ ∃ j0. i * i = j0 * 10

Rule argument

pos: right 1

Additional information