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Proof step 8 from proof mod-square-10 (previous step)

prime(2) ∧ ¬ 2 | i * i → 2 * 5 * j ≠ i * i, i * i = j * 10 ⊦ i % 10 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
i * i = j * 10, 2 | j * 10 ⊦ i % 10 = 0

Rule argument

Additional information

Used simplifier rules: prime-two-01: ⊦ prime(2);%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult