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Proof step 2 from proof pot-isSquare (previous step)

0 < i, 0 < j ⊦ isSquare(i ^ j) ↔ isSquare(i) ∨ even(j)

User applied rule case distinction

And obtained the following new goals

Proof step 3:
isSquare(i ^ j), 0 < i, 0 < j ⊦ isSquare(i) ∨ even(j)
Proof step 16:
isSquare(i) ∨ even(j), 0 < i, 0 < j ⊦ isSquare(i ^ j)

Rule argument

pos: right 1

Additional information