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Proof step 21 from proof pot-isSquare (previous step)

0 < j, 0 < j0 * j0 ⊦ isSquare((j0 * j0) ^ j)

User applied rule cut formula

And obtained the following new goals

Proof step 22:
0 < j, 0 < j0 * j0 ⊦ (j0 * j0) ^ j = j0 ^ j * j0 ^ j, isSquare((j0 * j0) ^ j)

Rule argument

fma: (j0 * j0) ^ j = j0 ^ j * j0 ^ j

Additional information

Used simplifier rules: isSquare-square: ⊦ isSquare(i * i); from specification int-square%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used formulas: (j0 * j0) ^ j = j0 ^ j * j0 ^ j