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Proof step 28 from proof pot-isSquare (previous step)

0 < i, 0 < j0 ⊦ isSquare(i), isSquare(i ^ (2 * j0))

User applied rule cut formula

And obtained the following new goals

Proof step 29:
0 < i, 0 < j0 ⊦ i ^ (2 * j0) = i ^ j0 * i ^ j0, isSquare(i), isSquare(i ^ (2 * j0))

Rule argument

fma: i ^ (2 * j0) = i ^ j0 * i ^ j0

Additional information

Used simplifier rules: isSquare-square: ⊦ isSquare(i * i); from specification int-square%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used formulas: i ^ (2 * j0) = i ^ j0 * i ^ j0