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Proof step 8 from proof pot-isSquare (previous step)

0 < j, isSquare(i ^ j -1 * i), 0 < i, 0 < j, ∀ j0, i. i→n(j0) < i→n(j) → isSquare(i ^ j0) ∧ 0 < i ∧ 0 < j0 → isSquare(i) ∨ even(j0) ⊦ isSquare(i), even(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
0 < i, 0 < j, isSquare(i ^ (j - 1) * i), ∀ j0, i. i→n(j0) < i→n(j) → isSquare(i ^ j0) ∧ 0 < i ∧ 0 < j0 → isSquare(i) ∨ even(j0) ⊦ isSquare(i), even(j)

Rule argument

Additional information

Used simplifier rules: sub-pred: ⊦ i -1 = i - 1; from specification int-abs