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Proof step 17 from proof prime-29 (previous step)

29 % i = 0, i * i ≤ 29, 0 < i, 1 < i, i ≤ 3 ⊦ i = 6, i = 5, i = 4

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ i ≠ j → (i ≤ j ↔ i ≤ j - 1)

Rule argument

spec: int-abs inst: name: le-rec seq: ⊦ i ≠ j → (i ≤ j ↔ i ≤ j - 1) subst: [j, i] → [3, i] flags: rewrite

Additional information

Used simplifier rules: num-between: i + 1 = i0 ⊦ (* i) < j → (j ≤ (* i0) ↔ j = i0); from specification int-abs Used terms: 3, i