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Proof step 8 from proof prime-29 (previous step)

29 % i = 0, i * i ≤ 29, 0 < i, 1 < i, i ≤ 6 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ i ≠ j → (i ≤ j ↔ i ≤ j - 1)
Proof step 10:
i ≠ 6, 29 % i = 0, i * i ≤ 29, 0 < i, 1 < i, i ≤ 6 - 1 ⊦

Rule argument

spec: int-abs inst: name: le-rec seq: ⊦ i ≠ j → (i ≤ j ↔ i ≤ j - 1) subst: [j, i] → [6, i] flags: rewrite

Additional information

Used terms: 6, i