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Proof step 16 from proof prime-43 (previous step)

43 % i = 0, i * i ≤ 43, 0 < i, 1 < i, i +1 = 5 ∨ i +1 < 5 ⊦ i = 6, i = 5

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
43 % i = 0, 1 < i, 0 < i, i * i ≤ 43, i < 4 ⊦ i = 5, i = 6, 4 = i

Rule argument

Additional information

Used simplifier rules: numls-03: ⊦ i + (* j) < (* j0) ↔ i < j0 - j; from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%numadd-01: ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0; from specification int-abs%succ-01: ⊦ i +1 = i + 1; from specification int-basic2