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Proof step 1 from proof prime-5 (conclusion)

⊦ prime(5)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ 1 < j → (prime(j) ↔ (∀ i. 1 < i ∧ i * i ≤ j → j % i ≠ 0))
Proof step 3:
1 < 5 ⊦ ∀ i. 1 < i ∧ i * i ≤ 5 → 5 % i ≠ 0

Rule argument

spec: inst: name: prime-def-mod seq: ⊦ 1 < j → (prime(j) ↔ (∀ i. 1 < i ∧ i * i ≤ j → j % i ≠ 0)) subst: [j] → [5] flags: rewrite, current

Additional information

Used terms: 5