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Proof step 7 from proof prime-7 (previous step)

7 % i = 0, 3 ≤ i, i * i ≤ 7, 0 < i, 0 ≤ i ⊦ 3 * 3 ≤ i * i

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-mult inst: name: square-le seq: ⊦ i * i ≤ j * j ↔ abs(i) ≤ abs(j) subst: [j, i] → [i, 3] flags: rewrite

Additional information

Used simplifier rules: abs-16: ⊦ 0 < j → abs(j) = j; from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%lenls: ⊦ i ≤ j → ¬ j < i; from specification int-abs Used terms: i, 3