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Proof step 18 from proof prime-def-mod (previous step)

0 ≤ i0, 2 ≤ i * i0, 0 < i, 2 < i * i0, 1 < i, 1 < i0, 0 < i0, ∀ i1. 1 < i1 ∧ i1 * i1 ≤ i * i0 → (i * i0) % i1 ≠ 0 ⊦ i * i0 = 1

User applied rule all left

And obtained the following new goals

Proof step 19:
0 ≤ i0, 2 ≤ i * i0, 0 < i, 2 < i * i0, 1 < i, 1 < i0, 0 < i0, 1 < i ∧ i * i ≤ i * i0 → (i * i0) % i ≠ 0, ∀ i1. 1 < i1 ∧ i1 * i1 ≤ i * i0 → (i * i0) % i1 ≠ 0 ⊦ i * i0 = 1

Rule argument

pos: left 8 terms: i abort: F discard: F computed: F

Additional information

Used terms: i